y+1=-1/2(x+2) eching

$$y+1=- \frac{ 1 }{ 2 } (x+2)$$

x uchun yechish

$$x=-2y-4$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-\frac{1}{2} ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y+1=-\frac{1}{2}x-1$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$-\frac{1}{2}x-1=y+1$$

1 ni ikki tarafga qo’shing.

$$-\frac{1}{2}x=y+1+1$$

2 olish uchun 1 va 1'ni qo'shing.

$$-\frac{1}{2}x=y+2$$

Ikkala tarafini -2 ga ko‘paytiring.

$$\frac{-\frac{1}{2}x}{-\frac{1}{2}}=\frac{y+2}{-\frac{1}{2}}$$

-\frac{1}{2} ga bo'lish -\frac{1}{2} ga ko'paytirishni bekor qiladi.

$$x=\frac{y+2}{-\frac{1}{2}}$$

y+2 ni -\frac{1}{2} ga bo'lish y+2 ga k'paytirish -\frac{1}{2} ga qaytarish.

$$x=-2y-4$$

y uchun yechish

$$y=-\frac{x}{2}-2$$

Yechim qadamlari

-\frac{1}{2} ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y+1=-\frac{1}{2}x-1$$

Ikkala tarafdan 1 ni ayirish.

$$y=-\frac{1}{2}x-1-1$$

-2 olish uchun -1 dan 1 ni ayirish.

$$y=-\frac{1}{2}x-2$$