y+1=3/2*(x-1) eching

$$y+1= \frac{ 3 }{ 2 } \times (x-1)$$

x uchun yechish

$$x=\frac{2y+5}{3}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{3}{2} ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y+1=\frac{3}{2}x-\frac{3}{2}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{3}{2}x-\frac{3}{2}=y+1$$

\frac{3}{2} ni ikki tarafga qo’shing.

$$\frac{3}{2}x=y+1+\frac{3}{2}$$

\frac{5}{2} olish uchun 1 va \frac{3}{2}'ni qo'shing.

$$\frac{3}{2}x=y+\frac{5}{2}$$

Tenglamaning ikki tarafini \frac{3}{2} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{\frac{3}{2}x}{\frac{3}{2}}=\frac{y+\frac{5}{2}}{\frac{3}{2}}$$

\frac{3}{2} ga bo'lish \frac{3}{2} ga ko'paytirishni bekor qiladi.

$$x=\frac{y+\frac{5}{2}}{\frac{3}{2}}$$

y+\frac{5}{2} ni \frac{3}{2} ga bo'lish y+\frac{5}{2} ga k'paytirish \frac{3}{2} ga qaytarish.

$$x=\frac{2y+5}{3}$$

y uchun yechish

$$y=\frac{3x-5}{2}$$

Yechim qadamlari

\frac{3}{2} ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y+1=\frac{3}{2}x-\frac{3}{2}$$

Ikkala tarafdan 1 ni ayirish.

$$y=\frac{3}{2}x-\frac{3}{2}-1$$

-\frac{5}{2} olish uchun -\frac{3}{2} dan 1 ni ayirish.

$$y=\frac{3}{2}x-\frac{5}{2}$$