y-6=2/15(x-5) eching

$$y - 6 = \frac { 2 } { 15 } ( x - 5 )$$

x uchun yechish

$$x=\frac{15y}{2}-40$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{2}{15} ga x-5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-6=\frac{2}{15}x-\frac{2}{3}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{2}{15}x-\frac{2}{3}=y-6$$

\frac{2}{3} ni ikki tarafga qo’shing.

$$\frac{2}{15}x=y-6+\frac{2}{3}$$

-\frac{16}{3} olish uchun -6 va \frac{2}{3}'ni qo'shing.

$$\frac{2}{15}x=y-\frac{16}{3}$$

Tenglamaning ikki tarafini \frac{2}{15} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{\frac{2}{15}x}{\frac{2}{15}}=\frac{y-\frac{16}{3}}{\frac{2}{15}}$$

\frac{2}{15} ga bo'lish \frac{2}{15} ga ko'paytirishni bekor qiladi.

$$x=\frac{y-\frac{16}{3}}{\frac{2}{15}}$$

y-\frac{16}{3} ni \frac{2}{15} ga bo'lish y-\frac{16}{3} ga k'paytirish \frac{2}{15} ga qaytarish.

$$x=\frac{15y}{2}-40$$

y uchun yechish

$$y=\frac{2\left(x+40\right)}{15}$$

Yechim qadamlari

\frac{2}{15} ga x-5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-6=\frac{2}{15}x-\frac{2}{3}$$

6 ni ikki tarafga qo’shing.

$$y=\frac{2}{15}x-\frac{2}{3}+6$$

\frac{16}{3} olish uchun -\frac{2}{3} va 6'ni qo'shing.

$$y=\frac{2}{15}x+\frac{16}{3}$$