y-5=-2/3(x+1) eching

$$y - 5 = - \frac { 2 } { 3 } ( x + 1 )$$

x uchun yechish

$$x=\frac{13-3y}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-\frac{2}{3} ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-5=-\frac{2}{3}x-\frac{2}{3}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$-\frac{2}{3}x-\frac{2}{3}=y-5$$

\frac{2}{3} ni ikki tarafga qo’shing.

$$-\frac{2}{3}x=y-5+\frac{2}{3}$$

-\frac{13}{3} olish uchun -5 va \frac{2}{3}'ni qo'shing.

$$-\frac{2}{3}x=y-\frac{13}{3}$$

Tenglamaning ikki tarafini -\frac{2}{3} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y-\frac{13}{3}}{-\frac{2}{3}}$$

-\frac{2}{3} ga bo'lish -\frac{2}{3} ga ko'paytirishni bekor qiladi.

$$x=\frac{y-\frac{13}{3}}{-\frac{2}{3}}$$

y-\frac{13}{3} ni -\frac{2}{3} ga bo'lish y-\frac{13}{3} ga k'paytirish -\frac{2}{3} ga qaytarish.

$$x=\frac{13-3y}{2}$$

y uchun yechish

$$y=\frac{13-2x}{3}$$

Yechim qadamlari

-\frac{2}{3} ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-5=-\frac{2}{3}x-\frac{2}{3}$$

5 ni ikki tarafga qo’shing.

$$y=-\frac{2}{3}x-\frac{2}{3}+5$$

\frac{13}{3} olish uchun -\frac{2}{3} va 5'ni qo'shing.

$$y=-\frac{2}{3}x+\frac{13}{3}$$