y-4=-2/3(x+2) eching

$$y - 4 = - \frac { 2 } { 3 } ( x + 2 )$$

x uchun yechish

$$x=-\frac{3y}{2}+4$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-\frac{2}{3} ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-4=-\frac{2}{3}x-\frac{4}{3}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$-\frac{2}{3}x-\frac{4}{3}=y-4$$

\frac{4}{3} ni ikki tarafga qo’shing.

$$-\frac{2}{3}x=y-4+\frac{4}{3}$$

-\frac{8}{3} olish uchun -4 va \frac{4}{3}'ni qo'shing.

$$-\frac{2}{3}x=y-\frac{8}{3}$$

Tenglamaning ikki tarafini -\frac{2}{3} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y-\frac{8}{3}}{-\frac{2}{3}}$$

-\frac{2}{3} ga bo'lish -\frac{2}{3} ga ko'paytirishni bekor qiladi.

$$x=\frac{y-\frac{8}{3}}{-\frac{2}{3}}$$

y-\frac{8}{3} ni -\frac{2}{3} ga bo'lish y-\frac{8}{3} ga k'paytirish -\frac{2}{3} ga qaytarish.

$$x=-\frac{3y}{2}+4$$

y uchun yechish

$$y=\frac{8-2x}{3}$$

Yechim qadamlari

-\frac{2}{3} ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-4=-\frac{2}{3}x-\frac{4}{3}$$

4 ni ikki tarafga qo’shing.

$$y=-\frac{2}{3}x-\frac{4}{3}+4$$

\frac{8}{3} olish uchun -\frac{4}{3} va 4'ni qo'shing.

$$y=-\frac{2}{3}x+\frac{8}{3}$$