ysqrt{2x}=12 eching

$$y \sqrt{ 2x } =12$$

y uchun yechish (complex solution)

$$y=6\sqrt{2}x^{-\frac{1}{2}}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglama standart shaklda.

$$\sqrt{2x}y=12$$

Ikki tarafini \sqrt{2x} ga bo‘ling.

$$\frac{\sqrt{2x}y}{\sqrt{2x}}=\frac{12}{\sqrt{2x}}$$

\sqrt{2x} ga bo'lish \sqrt{2x} ga ko'paytirishni bekor qiladi.

$$y=\frac{12}{\sqrt{2x}}$$

12 ni \sqrt{2x} ga bo'lish.

$$y=12\times \left(2x\right)^{-\frac{1}{2}}$$

x uchun yechish

$$x=\frac{72}{y^{2}}$$

$$y>0$$

Ildizli tenglamalarni yechish qadamlari

Ikki tarafini y ga bo‘ling.

$$\frac{y\sqrt{2x}}{y}=\frac{12}{y}$$

y ga bo'lish y ga ko'paytirishni bekor qiladi.

$$\sqrt{2x}=\frac{12}{y}$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$2x=\frac{144}{y^{2}}$$

Ikki tarafini 2 ga bo‘ling.

$$\frac{2x}{2}=\frac{144}{2y^{2}}$$

2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.

$$x=\frac{144}{2y^{2}}$$

\frac{144}{y^{2}} ni 2 ga bo'lish.

$$x=\frac{72}{y^{2}}$$

y uchun yechish

$$y=6\sqrt{\frac{2}{x}}$$

$$x>0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglama standart shaklda.

$$\sqrt{2x}y=12$$

Ikki tarafini \sqrt{2x} ga bo‘ling.

$$\frac{\sqrt{2x}y}{\sqrt{2x}}=\frac{12}{\sqrt{2x}}$$

\sqrt{2x} ga bo'lish \sqrt{2x} ga ko'paytirishni bekor qiladi.

$$y=\frac{12}{\sqrt{2x}}$$

x uchun yechish (complex solution)

$$x=\frac{72}{y^{2}}$$

$$arg(\sqrt{\frac{1}{y^{2}}}y)<\pi \text{ and }y\neq 0$$