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y^{2}-y-28=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
y=\frac{-\left(-1\right)±\sqrt{1-4\left(-28\right)}}{2}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
y=\frac{-\left(-1\right)±\sqrt{1+112}}{2}
-4 ni -28 marotabaga ko'paytirish.
y=\frac{-\left(-1\right)±\sqrt{113}}{2}
1 ni 112 ga qo'shish.
y=\frac{1±\sqrt{113}}{2}
-1 ning teskarisi 1 ga teng.
y=\frac{\sqrt{113}+1}{2}
y=\frac{1±\sqrt{113}}{2} tenglamasini yeching, bunda ± musbat. 1 ni \sqrt{113} ga qo'shish.
y=\frac{1-\sqrt{113}}{2}
y=\frac{1±\sqrt{113}}{2} tenglamasini yeching, bunda ± manfiy. 1 dan \sqrt{113} ni ayirish.
y^{2}-y-28=\left(y-\frac{\sqrt{113}+1}{2}\right)\left(y-\frac{1-\sqrt{113}}{2}\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{1+\sqrt{113}}{2} ga va x_{2} uchun \frac{1-\sqrt{113}}{2} ga bo‘ling.