y^2-8x-4y+4=0 eching

$$y ^ { 2 } - 8 x - 4 y + 4 = 0$$

x uchun yechish

$$x=\frac{\left(y-2\right)^{2}}{8}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan y^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-8x-4y+4=-y^{2}$$

4y ni ikki tarafga qo’shing.

$$-8x+4=-y^{2}+4y$$

Ikkala tarafdan 4 ni ayirish.

$$-8x=-y^{2}+4y-4$$

Ikki tarafini -8 ga bo‘ling.

$$\frac{-8x}{-8}=-\frac{\left(y-2\right)^{2}}{-8}$$

-8 ga bo'lish -8 ga ko'paytirishni bekor qiladi.

$$x=-\frac{\left(y-2\right)^{2}}{-8}$$

-\left(y-2\right)^{2} ni -8 ga bo'lish.

$$x=\frac{\left(y-2\right)^{2}}{8}$$

y uchun yechish (complex solution)

$$y=2\sqrt{2x}+2$$

$$y=-2\sqrt{2x}+2$$

y uchun yechish

$$y=2\sqrt{2x}+2$$

$$y=-2\sqrt{2x}+2\text{, }x\geq 0$$