y^2+5y-7 eching

$$y ^ { 2 } + 5 y - 7$$

Omil

$$\left(y-\frac{-\sqrt{53}-5}{2}\right)\left(y-\frac{\sqrt{53}-5}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$y^{2}+5y-7=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$y=\frac{-5±\sqrt{5^{2}-4\left(-7\right)}}{2}$$

5 kvadratini chiqarish.

$$y=\frac{-5±\sqrt{25-4\left(-7\right)}}{2}$$

-4 ni -7 marotabaga ko'paytirish.

$$y=\frac{-5±\sqrt{25+28}}{2}$$

25 ni 28 ga qo'shish.

$$y=\frac{-5±\sqrt{53}}{2}$$

y=\frac{-5±\sqrt{53}}{2} tenglamasini yeching, bunda ± musbat. -5 ni \sqrt{53} ga qo'shish.

$$y=\frac{\sqrt{53}-5}{2}$$

y=\frac{-5±\sqrt{53}}{2} tenglamasini yeching, bunda ± manfiy. -5 dan \sqrt{53} ni ayirish.

$$y=\frac{-\sqrt{53}-5}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-5+\sqrt{53}}{2} ga va x_{2} uchun \frac{-5-\sqrt{53}}{2} ga bo‘ling.

$$y^{2}+5y-7=\left(y-\frac{\sqrt{53}-5}{2}\right)\left(y-\frac{-\sqrt{53}-5}{2}\right)$$

Baholash

$$y^{2}+5y-7$$