y^2+3y eching

$$y ^ { 2 } + 3 y$$

Omil

$$y\left(y+3\right)$$

Yechim qadamlari

y omili.

$$y\left(y+3\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$y^{2}+3y=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$y=\frac{-3±\sqrt{3^{2}}}{2}$$

3^{2} ning kvadrat ildizini chiqarish.

$$y=\frac{-3±3}{2}$$

y=\frac{-3±3}{2} tenglamasini yeching, bunda ± musbat. -3 ni 3 ga qo'shish.

$$y=\frac{0}{2}$$

0 ni 2 ga bo'lish.

$$y=0$$

y=\frac{-3±3}{2} tenglamasini yeching, bunda ± manfiy. -3 dan 3 ni ayirish.

$$y=-\frac{6}{2}$$

-6 ni 2 ga bo'lish.

$$y=-3$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -3 ga bo‘ling.

$$y^{2}+3y=y\left(y-\left(-3\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$y^{2}+3y=y\left(y+3\right)$$

Baholash

$$y\left(y+3\right)$$