y^2+17y+5 eching

$$y ^ { 2 } + 17 y + 5$$

Omil

$$\left(y-\frac{-\sqrt{269}-17}{2}\right)\left(y-\frac{\sqrt{269}-17}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$y^{2}+17y+5=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$y=\frac{-17±\sqrt{17^{2}-4\times 5}}{2}$$

17 kvadratini chiqarish.

$$y=\frac{-17±\sqrt{289-4\times 5}}{2}$$

-4 ni 5 marotabaga ko'paytirish.

$$y=\frac{-17±\sqrt{289-20}}{2}$$

289 ni -20 ga qo'shish.

$$y=\frac{-17±\sqrt{269}}{2}$$

y=\frac{-17±\sqrt{269}}{2} tenglamasini yeching, bunda ± musbat. -17 ni \sqrt{269} ga qo'shish.

$$y=\frac{\sqrt{269}-17}{2}$$

y=\frac{-17±\sqrt{269}}{2} tenglamasini yeching, bunda ± manfiy. -17 dan \sqrt{269} ni ayirish.

$$y=\frac{-\sqrt{269}-17}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-17+\sqrt{269}}{2} ga va x_{2} uchun \frac{-17-\sqrt{269}}{2} ga bo‘ling.

$$y^{2}+17y+5=\left(y-\frac{\sqrt{269}-17}{2}\right)\left(y-\frac{-\sqrt{269}-17}{2}\right)$$

Baholash

$$y^{2}+17y+5$$