y=h(x+1)+3? eching

$$y = h ( x + 1 ) + 3 ?$$

h uchun yechish (complex solution)

$$\left\{\begin{matrix}h=-\frac{3-y}{x+1}\text{, }&x\neq -1\\h\in \mathrm{C}\text{, }&y=3\text{ and }x=-1\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

h ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y=hx+h+3$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$hx+h+3=y$$

Ikkala tarafdan 3 ni ayirish.

$$hx+h=y-3$$

h'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x+1\right)h=y-3$$

Ikki tarafini x+1 ga bo‘ling.

$$\frac{\left(x+1\right)h}{x+1}=\frac{y-3}{x+1}$$

x+1 ga bo'lish x+1 ga ko'paytirishni bekor qiladi.

$$h=\frac{y-3}{x+1}$$

x uchun yechish (complex solution)

$$\left\{\begin{matrix}x=-\frac{3+h-y}{h}\text{, }&h\neq 0\\x\in \mathrm{C}\text{, }&y=3\text{ and }h=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

h ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y=hx+h+3$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$hx+h+3=y$$

Ikkala tarafdan h ni ayirish.

$$hx+3=y-h$$

Ikkala tarafdan 3 ni ayirish.

$$hx=y-h-3$$

Ikki tarafini h ga bo‘ling.

$$\frac{hx}{h}=\frac{y-h-3}{h}$$

h ga bo'lish h ga ko'paytirishni bekor qiladi.

$$x=\frac{y-h-3}{h}$$

h uchun yechish

$$\left\{\begin{matrix}h=-\frac{3-y}{x+1}\text{, }&x\neq -1\\h\in \mathrm{R}\text{, }&y=3\text{ and }x=-1\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

h ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y=hx+h+3$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$hx+h+3=y$$

Ikkala tarafdan 3 ni ayirish.

$$hx+h=y-3$$

h'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x+1\right)h=y-3$$

Ikki tarafini x+1 ga bo‘ling.

$$\frac{\left(x+1\right)h}{x+1}=\frac{y-3}{x+1}$$

x+1 ga bo'lish x+1 ga ko'paytirishni bekor qiladi.

$$h=\frac{y-3}{x+1}$$

x uchun yechish

$$\left\{\begin{matrix}x=-\frac{3+h-y}{h}\text{, }&h\neq 0\\x\in \mathrm{R}\text{, }&y=3\text{ and }h=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

h ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y=hx+h+3$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$hx+h+3=y$$

Ikkala tarafdan h ni ayirish.

$$hx+3=y-h$$

Ikkala tarafdan 3 ni ayirish.

$$hx=y-h-3$$

Ikki tarafini h ga bo‘ling.

$$\frac{hx}{h}=\frac{y-h-3}{h}$$

h ga bo'lish h ga ko'paytirishni bekor qiladi.

$$x=\frac{y-h-3}{h}$$