y=dx^2 eching

$$y = d x ^ { 2 }$$

d uchun yechish (complex solution)

$$\left\{\begin{matrix}d=\frac{y}{x^{2}}\text{, }&x\neq 0\\d\in \mathrm{C}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$dx^{2}=y$$

Tenglama standart shaklda.

$$x^{2}d=y$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}d}{x^{2}}=\frac{y}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$d=\frac{y}{x^{2}}$$

d uchun yechish

$$\left\{\begin{matrix}d=\frac{y}{x^{2}}\text{, }&x\neq 0\\d\in \mathrm{R}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$dx^{2}=y$$

Tenglama standart shaklda.

$$x^{2}d=y$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}d}{x^{2}}=\frac{y}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$d=\frac{y}{x^{2}}$$

x uchun yechish (complex solution)

$$\left\{\begin{matrix}x=-d^{-\frac{1}{2}}\sqrt{y}\text{; }x=d^{-\frac{1}{2}}\sqrt{y}\text{, }&d\neq 0\\x\in \mathrm{C}\text{, }&y=0\text{ and }d=0\end{matrix}\right,$$

x uchun yechish

$$\left\{\begin{matrix}x=\sqrt{\frac{y}{d}}\text{; }x=-\sqrt{\frac{y}{d}}\text{, }&\left(y\geq 0\text{ and }d>0\right)\text{ or }\left(y\leq 0\text{ and }d<0\right)\\x\in \mathrm{R}\text{, }&y=0\text{ and }d=0\end{matrix}\right,$$