y=b^2+ax eching

$$y = b ^ { 2 } + a x$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=-\frac{b^{2}-y}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&y=b^{2}\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$b^{2}+ax=y$$

Ikkala tarafdan b^{2} ni ayirish.

$$ax=y-b^{2}$$

Tenglama standart shaklda.

$$xa=y-b^{2}$$

Ikki tarafini x ga bo‘ling.

$$\frac{xa}{x}=\frac{y-b^{2}}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$a=\frac{y-b^{2}}{x}$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{b^{2}-y}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&y=b^{2}\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$b^{2}+ax=y$$

Ikkala tarafdan b^{2} ni ayirish.

$$ax=y-b^{2}$$

Tenglama standart shaklda.

$$xa=y-b^{2}$$

Ikki tarafini x ga bo‘ling.

$$\frac{xa}{x}=\frac{y-b^{2}}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$a=\frac{y-b^{2}}{x}$$

b uchun yechish (complex solution)

$$b=-\sqrt{y-ax}$$

$$b=\sqrt{y-ax}$$

b uchun yechish

$$b=\sqrt{y-ax}$$

$$b=-\sqrt{y-ax}\text{, }y\geq ax$$