y=ax^3+bx^2 eching

$$y = a x ^ { 3 } + b x ^ { 2 }$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=\frac{y-bx^{2}}{x^{3}}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ax^{3}+bx^{2}=y$$

Ikkala tarafdan bx^{2} ni ayirish.

$$ax^{3}=y-bx^{2}$$

Shartlarni qayta saralash.

$$ax^{3}=-bx^{2}+y$$

Tenglama standart shaklda.

$$x^{3}a=y-bx^{2}$$

Ikki tarafini x^{3} ga bo‘ling.

$$\frac{x^{3}a}{x^{3}}=\frac{y-bx^{2}}{x^{3}}$$

x^{3} ga bo'lish x^{3} ga ko'paytirishni bekor qiladi.

$$a=\frac{y-bx^{2}}{x^{3}}$$

y-bx^{2} ni x^{3} ga bo'lish.

$$a=-\frac{b}{x}+\frac{y}{x^{3}}$$

b uchun yechish (complex solution)

$$\left\{\begin{matrix}b=-ax+\frac{y}{x^{2}}\text{, }&x\neq 0\\b\in \mathrm{C}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ax^{3}+bx^{2}=y$$

Ikkala tarafdan ax^{3} ni ayirish.

$$bx^{2}=y-ax^{3}$$

Shartlarni qayta saralash.

$$bx^{2}=-ax^{3}+y$$

Tenglama standart shaklda.

$$x^{2}b=y-ax^{3}$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}b}{x^{2}}=\frac{y-ax^{3}}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$b=\frac{y-ax^{3}}{x^{2}}$$

y-ax^{3} ni x^{2} ga bo'lish.

$$b=-ax+\frac{y}{x^{2}}$$

a uchun yechish

$$\left\{\begin{matrix}a=\frac{y-bx^{2}}{x^{3}}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ax^{3}+bx^{2}=y$$

Ikkala tarafdan bx^{2} ni ayirish.

$$ax^{3}=y-bx^{2}$$

Shartlarni qayta saralash.

$$ax^{3}=-bx^{2}+y$$

Tenglama standart shaklda.

$$x^{3}a=y-bx^{2}$$

Ikki tarafini x^{3} ga bo‘ling.

$$\frac{x^{3}a}{x^{3}}=\frac{y-bx^{2}}{x^{3}}$$

x^{3} ga bo'lish x^{3} ga ko'paytirishni bekor qiladi.

$$a=\frac{y-bx^{2}}{x^{3}}$$

y-bx^{2} ni x^{3} ga bo'lish.

$$a=-\frac{b}{x}+\frac{y}{x^{3}}$$

b uchun yechish

$$\left\{\begin{matrix}b=-ax+\frac{y}{x^{2}}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ax^{3}+bx^{2}=y$$

Ikkala tarafdan ax^{3} ni ayirish.

$$bx^{2}=y-ax^{3}$$

Shartlarni qayta saralash.

$$bx^{2}=-ax^{3}+y$$

Tenglama standart shaklda.

$$x^{2}b=y-ax^{3}$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}b}{x^{2}}=\frac{y-ax^{3}}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$b=\frac{y-ax^{3}}{x^{2}}$$

y-ax^{3} ni x^{2} ga bo'lish.

$$b=-ax+\frac{y}{x^{2}}$$