y=ax^2 eching

$$y = a x ^ { 2 }$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=\frac{y}{x^{2}}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ax^{2}=y$$

Tenglama standart shaklda.

$$x^{2}a=y$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}a}{x^{2}}=\frac{y}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$a=\frac{y}{x^{2}}$$

a uchun yechish

$$\left\{\begin{matrix}a=\frac{y}{x^{2}}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ax^{2}=y$$

Tenglama standart shaklda.

$$x^{2}a=y$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}a}{x^{2}}=\frac{y}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$a=\frac{y}{x^{2}}$$

x uchun yechish (complex solution)

$$\left\{\begin{matrix}x=-a^{-\frac{1}{2}}\sqrt{y}\text{; }x=a^{-\frac{1}{2}}\sqrt{y}\text{, }&a\neq 0\\x\in \mathrm{C}\text{, }&y=0\text{ and }a=0\end{matrix}\right,$$

x uchun yechish

$$\left\{\begin{matrix}x=\sqrt{\frac{y}{a}}\text{; }x=-\sqrt{\frac{y}{a}}\text{, }&\left(y\geq 0\text{ and }a>0\right)\text{ or }\left(y\leq 0\text{ and }a<0\right)\\x\in \mathrm{R}\text{, }&y=0\text{ and }a=0\end{matrix}\right,$$