y=2sqrt{x-3} eching

$$y = 2 \sqrt { x - 3 }$$

x uchun yechish

$$x=\frac{y^{2}+12}{4}$$

$$y\geq 0$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$2\sqrt{x-3}=y$$

Ikki tarafini 2 ga bo‘ling.

$$\frac{2\sqrt{x-3}}{2}=\frac{y}{2}$$

2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.

$$\sqrt{x-3}=\frac{y}{2}$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$x-3=\frac{y^{2}}{4}$$

3 ni tenglamaning ikkala tarafiga qo'shish.

$$x-3-\left(-3\right)=\frac{y^{2}}{4}-\left(-3\right)$$

O‘zidan -3 ayirilsa 0 qoladi.

$$x=\frac{y^{2}}{4}-\left(-3\right)$$

\frac{y^{2}}{4} dan -3 ni ayirish.

$$x=\frac{y^{2}}{4}+3$$

x uchun yechish (complex solution)

$$x=\frac{y^{2}+12}{4}$$

$$arg(y)<\pi \text{ or }y=0$$

y uchun yechish

$$y=2\sqrt{x-3}$$

$$x\geq 3$$