y=2+1/x+3 eching

$$y = 2 + \frac { 1 } { x + 3 }$$

x uchun yechish

$$x=-\frac{7-3y}{2-y}$$

$$y\neq 2$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati -3 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x+3 ga ko'paytirish.

$$y\left(x+3\right)=\left(x+3\right)\times 2+1$$

y ga x+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$yx+3y=\left(x+3\right)\times 2+1$$

x+3 ga 2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$yx+3y=2x+6+1$$

7 olish uchun 6 va 1'ni qo'shing.

$$yx+3y=2x+7$$

Ikkala tarafdan 2x ni ayirish.

$$yx+3y-2x=7$$

Ikkala tarafdan 3y ni ayirish.

$$yx-2x=7-3y$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(y-2\right)x=7-3y$$

Ikki tarafini y-2 ga bo‘ling.

$$\frac{\left(y-2\right)x}{y-2}=\frac{7-3y}{y-2}$$

y-2 ga bo'lish y-2 ga ko'paytirishni bekor qiladi.

$$x=\frac{7-3y}{y-2}$$

x qiymati -3 teng bo‘lmaydi.

$$x=\frac{7-3y}{y-2}\text{, }x\neq -3$$

y uchun yechish

$$y=\frac{2x+7}{x+3}$$

$$x\neq -3$$