a uchun yechish (complex solution)
\left\{\begin{matrix}a=\frac{y}{5dnt}\text{, }&t\neq 0\text{ and }n\neq 0\text{ and }d\neq 0\\a\in \mathrm{C}\text{, }&\left(d=0\text{ or }n=0\text{ or }t=0\right)\text{ and }y=0\end{matrix}\right,
d uchun yechish (complex solution)
\left\{\begin{matrix}d=\frac{y}{5ant}\text{, }&t\neq 0\text{ and }n\neq 0\text{ and }a\neq 0\\d\in \mathrm{C}\text{, }&\left(a=0\text{ or }n=0\text{ or }t=0\right)\text{ and }y=0\end{matrix}\right,
a uchun yechish
\left\{\begin{matrix}a=\frac{y}{5dnt}\text{, }&t\neq 0\text{ and }n\neq 0\text{ and }d\neq 0\\a\in \mathrm{R}\text{, }&\left(d=0\text{ or }n=0\text{ or }t=0\right)\text{ and }y=0\end{matrix}\right,
d uchun yechish
\left\{\begin{matrix}d=\frac{y}{5ant}\text{, }&t\neq 0\text{ and }n\neq 0\text{ and }a\neq 0\\d\in \mathrm{R}\text{, }&\left(a=0\text{ or }n=0\text{ or }t=0\right)\text{ and }y=0\end{matrix}\right,
Grafik
Baham ko'rish
Klipbordga nusxa olish
5dant=y
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
5dnta=y
Tenglama standart shaklda.
\frac{5dnta}{5dnt}=\frac{y}{5dnt}
Ikki tarafini 5dnt ga bo‘ling.
a=\frac{y}{5dnt}
5dnt ga bo'lish 5dnt ga ko'paytirishni bekor qiladi.
5dant=y
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
5antd=y
Tenglama standart shaklda.
\frac{5antd}{5ant}=\frac{y}{5ant}
Ikki tarafini 5ant ga bo‘ling.
d=\frac{y}{5ant}
5ant ga bo'lish 5ant ga ko'paytirishni bekor qiladi.
5dant=y
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
5dnta=y
Tenglama standart shaklda.
\frac{5dnta}{5dnt}=\frac{y}{5dnt}
Ikki tarafini 5dnt ga bo‘ling.
a=\frac{y}{5dnt}
5dnt ga bo'lish 5dnt ga ko'paytirishni bekor qiladi.
5dant=y
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
5antd=y
Tenglama standart shaklda.
\frac{5antd}{5ant}=\frac{y}{5ant}
Ikki tarafini 5ant ga bo‘ling.
d=\frac{y}{5ant}
5ant ga bo'lish 5ant ga ko'paytirishni bekor qiladi.
Misollar
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