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\frac{1}{2}x-\frac{1}{3}y=y
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\frac{1}{2}x=y+\frac{1}{3}y
\frac{1}{3}y ni ikki tarafga qo’shing.
\frac{1}{2}x=\frac{4}{3}y
\frac{4}{3}y ni olish uchun y va \frac{1}{3}y ni birlashtirish.
\frac{1}{2}x=\frac{4y}{3}
Tenglama standart shaklda.
\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{4y}{\frac{1}{2}\times 3}
Ikkala tarafini 2 ga ko‘paytiring.
x=\frac{4y}{\frac{1}{2}\times 3}
\frac{1}{2} ga bo'lish \frac{1}{2} ga ko'paytirishni bekor qiladi.
x=\frac{8y}{3}
\frac{4y}{3} ni \frac{1}{2} ga bo'lish \frac{4y}{3} ga k'paytirish \frac{1}{2} ga qaytarish.
y+\frac{1}{3}y=\frac{1}{2}x
\frac{1}{3}y ni ikki tarafga qo’shing.
\frac{4}{3}y=\frac{1}{2}x
\frac{4}{3}y ni olish uchun y va \frac{1}{3}y ni birlashtirish.
\frac{4}{3}y=\frac{x}{2}
Tenglama standart shaklda.
\frac{\frac{4}{3}y}{\frac{4}{3}}=\frac{x}{\frac{4}{3}\times 2}
Tenglamaning ikki tarafini \frac{4}{3} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.
y=\frac{x}{\frac{4}{3}\times 2}
\frac{4}{3} ga bo'lish \frac{4}{3} ga ko'paytirishni bekor qiladi.
y=\frac{3x}{8}
\frac{x}{2} ni \frac{4}{3} ga bo'lish \frac{x}{2} ga k'paytirish \frac{4}{3} ga qaytarish.