y=sqrt{x-3}+2 eching

$$y = \sqrt { x - 3 } + 2$$

x uchun yechish

$$x=\left(2-y\right)^{2}+3$$

$$-\left(2-y\right)\geq 0$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\sqrt{x-3}+2=y$$

Ikkala tarafdan 2 ni ayirish.

$$\sqrt{x-3}=y-2$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$x-3=\left(y-2\right)^{2}$$

3 ni tenglamaning ikkala tarafiga qo'shish.

$$x-3-\left(-3\right)=\left(y-2\right)^{2}-\left(-3\right)$$

O‘zidan -3 ayirilsa 0 qoladi.

$$x=\left(y-2\right)^{2}-\left(-3\right)$$

\left(y-2\right)^{2} dan -3 ni ayirish.

$$x=\left(y-2\right)^{2}+3$$

x uchun yechish (complex solution)

$$x=\left(2-y\right)^{2}+3$$

$$y=2\text{ or }arg(2-y)\geq \pi$$

y uchun yechish

$$y=\sqrt{x-3}+2$$

$$x\geq 3$$