y=sqrt{-x}+1 eching

$$y = \sqrt { - x } + 1$$

x uchun yechish

$$x=-\left(1-y\right)^{2}$$

$$-\left(1-y\right)\geq 0$$

Ildizli tenglamalarni yechish qadamlari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\sqrt{-x}+1=y$$

Ikkala tarafdan 1 ni ayirish.

$$\sqrt{-x}=y-1$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$-x=\left(y-1\right)^{2}$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-x}{-1}=\frac{\left(y-1\right)^{2}}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$x=\frac{\left(y-1\right)^{2}}{-1}$$

\left(y-1\right)^{2} ni -1 ga bo'lish.

$$x=-\left(y-1\right)^{2}$$

x uchun yechish (complex solution)

$$x=-\left(1-y\right)^{2}$$

$$y=1\text{ or }arg(1-y)\geq \pi$$

y uchun yechish

$$y=\sqrt{-x}+1$$

$$x\leq 0$$