y=1/x-4+3 eching

$$y = \frac { 1 } { x - 4 } + 3$$

x uchun yechish

$$x=-\frac{4y-11}{3-y}$$

$$y\neq 3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati 4 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x-4 ga ko'paytirish.

$$y\left(x-4\right)=1+\left(x-4\right)\times 3$$

y ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$yx-4y=1+\left(x-4\right)\times 3$$

x-4 ga 3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$yx-4y=1+3x-12$$

-11 olish uchun 1 dan 12 ni ayirish.

$$yx-4y=-11+3x$$

Ikkala tarafdan 3x ni ayirish.

$$yx-4y-3x=-11$$

4y ni ikki tarafga qo’shing.

$$yx-3x=-11+4y$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(y-3\right)x=-11+4y$$

Tenglama standart shaklda.

$$\left(y-3\right)x=4y-11$$

Ikki tarafini y-3 ga bo‘ling.

$$\frac{\left(y-3\right)x}{y-3}=\frac{4y-11}{y-3}$$

y-3 ga bo'lish y-3 ga ko'paytirishni bekor qiladi.

$$x=\frac{4y-11}{y-3}$$

x qiymati 4 teng bo‘lmaydi.

$$x=\frac{4y-11}{y-3}\text{, }x\neq 4$$

y uchun yechish

$$y=-\frac{11-3x}{x-4}$$

$$x\neq 4$$