y=-2/2sqrt{x+2}+4 eching

$$y = \frac { - 2 } { 2 } \sqrt { x + 2 } + 4$$

x uchun yechish

$$x=\left(4-y\right)^{2}-2$$

$$4-y\geq 0$$

Ildizli tenglamalarni yechish qadamlari

-1 ni olish uchun -2 ni 2 ga bo‘ling.

$$y=-\sqrt{x+2}+4$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$-\sqrt{x+2}+4=y$$

Ikkala tarafdan 4 ni ayirish.

$$-\sqrt{x+2}=y-4$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-\sqrt{x+2}}{-1}=\frac{y-4}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$\sqrt{x+2}=\frac{y-4}{-1}$$

y-4 ni -1 ga bo'lish.

$$\sqrt{x+2}=4-y$$

Tenglamaning ikkala taraf kvadratini chiqarish.

$$x+2=\left(4-y\right)^{2}$$

Tenglamaning ikkala tarafidan 2 ni ayirish.

$$x+2-2=\left(4-y\right)^{2}-2$$

O‘zidan 2 ayirilsa 0 qoladi.

$$x=\left(4-y\right)^{2}-2$$

x uchun yechish (complex solution)

$$x=\left(4-y\right)^{2}-2$$

$$y=4\text{ or }arg(4-y)<\pi$$

y uchun yechish (complex solution)

$$y=-\sqrt{x+2}+4$$

y uchun yechish

$$y=-\sqrt{x+2}+4$$

$$x\geq -2$$