y=(-5)^2-4^2+(1/5)^0/3^-2+1? eching

$$y = \frac { ( - 5 ) ^ { 2 } - 4 ^ { 2 } + ( \frac { 1 } { 5 } ) ^ { 0 } } { 3 ^ { - 2 } + 1 } ?$$

y uchun yechish

$$y=9$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini -5 ga hisoblang va 25 ni qiymatni oling.

$$y=\frac{25-4^{2}+\left(\frac{1}{5}\right)^{0}}{3^{-2}+1}$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$y=\frac{25-16+\left(\frac{1}{5}\right)^{0}}{3^{-2}+1}$$

9 olish uchun 25 dan 16 ni ayirish.

$$y=\frac{9+\left(\frac{1}{5}\right)^{0}}{3^{-2}+1}$$

0 daraja ko‘rsatkichini \frac{1}{5} ga hisoblang va 1 ni qiymatni oling.

$$y=\frac{9+1}{3^{-2}+1}$$

10 olish uchun 9 va 1'ni qo'shing.

$$y=\frac{10}{3^{-2}+1}$$

-2 daraja ko‘rsatkichini 3 ga hisoblang va \frac{1}{9} ni qiymatni oling.

$$y=\frac{10}{\frac{1}{9}+1}$$

\frac{10}{9} olish uchun \frac{1}{9} va 1'ni qo'shing.

$$y=\frac{10}{\frac{10}{9}}$$

10 ni \frac{10}{9} ga bo'lish 10 ga k'paytirish \frac{10}{9} ga qaytarish.

$$y=10\times \frac{9}{10}$$

9 hosil qilish uchun 10 va \frac{9}{10} ni ko'paytirish.

$$y=9$$

y'ni tayinlash

$$y≔9$$