y=exp(x) eching

$$y = \exp ( x )$$

p uchun yechish (complex solution)

$$\left\{\begin{matrix}p=\frac{y}{ex^{2}}\text{, }&x\neq 0\\p\in \mathrm{C}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$y=ex^{2}p$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ex^{2}p=y$$

Ikki tarafini ex^{2} ga bo‘ling.

$$\frac{ex^{2}p}{ex^{2}}=\frac{y}{ex^{2}}$$

ex^{2} ga bo'lish ex^{2} ga ko'paytirishni bekor qiladi.

$$p=\frac{y}{ex^{2}}$$

p uchun yechish

$$\left\{\begin{matrix}p=\frac{y}{ex^{2}}\text{, }&x\neq 0\\p\in \mathrm{R}\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$y=ex^{2}p$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ex^{2}p=y$$

Ikki tarafini ex^{2} ga bo‘ling.

$$\frac{ex^{2}p}{ex^{2}}=\frac{y}{ex^{2}}$$

ex^{2} ga bo'lish ex^{2} ga ko'paytirishni bekor qiladi.

$$p=\frac{y}{ex^{2}}$$

x uchun yechish (complex solution)

$$\left\{\begin{matrix}x=-\left(ep\right)^{-\frac{1}{2}}\sqrt{y}\text{; }x=\left(ep\right)^{-\frac{1}{2}}\sqrt{y}\text{, }&p\neq 0\\x\in \mathrm{C}\text{, }&y=0\text{ and }p=0\end{matrix}\right,$$

x uchun yechish

$$\left\{\begin{matrix}x=\sqrt{\frac{y}{ep}}\text{; }x=-\sqrt{\frac{y}{ep}}\text{, }&\left(y\geq 0\text{ and }p>0\right)\text{ or }\left(y\leq 0\text{ and }p<0\right)\\x\in \mathrm{R}\text{, }&y=0\text{ and }p=0\end{matrix}\right,$$