y uchun yechish
y=\frac{x^{2}+x\Delta +1}{5}
x uchun yechish (complex solution)
x=\frac{\sqrt{20y+\Delta ^{2}-4}-\Delta }{2}
x=\frac{-\sqrt{20y+\Delta ^{2}-4}-\Delta }{2}
x uchun yechish
x=\frac{\sqrt{20y+\Delta ^{2}-4}-\Delta }{2}
x=\frac{-\sqrt{20y+\Delta ^{2}-4}-\Delta }{2}\text{, }y\geq -\frac{\Delta ^{2}}{20}+\frac{1}{5}
Grafik
Baham ko'rish
Klipbordga nusxa olish
5y=\Delta x+x^{2}+1
5y ni olish uchun y va 4y ni birlashtirish.
5y=x^{2}+x\Delta +1
Tenglama standart shaklda.
\frac{5y}{5}=\frac{x^{2}+x\Delta +1}{5}
Ikki tarafini 5 ga bo‘ling.
y=\frac{x^{2}+x\Delta +1}{5}
5 ga bo'lish 5 ga ko'paytirishni bekor qiladi.
Misollar
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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