xy=z(2-y) eching

$$xy=z(2-y)$$

x uchun yechish

$$\left\{\begin{matrix}x=-\frac{z\left(y-2\right)}{y}\text{, }&y\neq 0\\x\in \mathrm{R}\text{, }&z=0\text{ and }y=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

z ga 2-y ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$xy=2z-zy$$

Tenglama standart shaklda.

$$yx=2z-yz$$

Ikki tarafini y ga bo‘ling.

$$\frac{yx}{y}=\frac{z\left(2-y\right)}{y}$$

y ga bo'lish y ga ko'paytirishni bekor qiladi.

$$x=\frac{z\left(2-y\right)}{y}$$

y uchun yechish

$$\left\{\begin{matrix}y=\frac{2z}{x+z}\text{, }&x\neq -z\\y\in \mathrm{R}\text{, }&z=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

z ga 2-y ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$xy=2z-zy$$

zy ni ikki tarafga qo’shing.

$$xy+zy=2z$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x+z\right)y=2z$$

Ikki tarafini x+z ga bo‘ling.

$$\frac{\left(x+z\right)y}{x+z}=\frac{2z}{x+z}$$

x+z ga bo'lish x+z ga ko'paytirishni bekor qiladi.

$$y=\frac{2z}{x+z}$$