x-4+2x+182+x+4+1x+255 eching

$$x-4+2x+182+x+4+1x+255$$

Baholash

$$5x+437$$

Yechim qadamlari

3x ni olish uchun x va 2x ni birlashtirish.

$$3x-4+182+x+4+1x+255$$

178 olish uchun -4 va 182'ni qo'shing.

$$3x+178+x+4+1x+255$$

4x ni olish uchun 3x va x ni birlashtirish.

$$4x+178+4+1x+255$$

182 olish uchun 178 va 4'ni qo'shing.

$$4x+182+1x+255$$

5x ni olish uchun 4x va 1x ni birlashtirish.

$$5x+182+255$$

437 olish uchun 182 va 255'ni qo'shing.

$$5x+437$$

x ga nisbatan hosilani topish

$$5$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

3x ni olish uchun x va 2x ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-4+182+x+4+1x+255)$$

178 olish uchun -4 va 182'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+178+x+4+1x+255)$$

4x ni olish uchun 3x va x ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x+178+4+1x+255)$$

182 olish uchun 178 va 4'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x+182+1x+255)$$

5x ni olish uchun 4x va 1x ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5x+182+255)$$

437 olish uchun 182 va 255'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5x+437)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$5x^{1-1}$$

1 dan 1 ni ayirish.

$$5x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$5\times 1$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$5$$