x-20geq2left(x+4-20right) eching

$$x-20 \geq 2 \left( x+4-20 \right)$$

x uchun yechish

$$x\leq 12$$

Yechim qadamlari

-16 olish uchun 4 dan 20 ni ayirish.

$$x-20\geq 2\left(x-16\right)$$

2 ga x-16 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x-20\geq 2x-32$$

Ikkala tarafdan 2x ni ayirish.

$$x-20-2x\geq -32$$

-x ni olish uchun x va -2x ni birlashtirish.

$$-x-20\geq -32$$

20 ni ikki tarafga qo’shing.

$$-x\geq -32+20$$

-12 olish uchun -32 va 20'ni qo'shing.

$$-x\geq -12$$

Ikki tarafini -1 ga bo‘ling. -1 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\leq \frac{-12}{-1}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-12}{-1} kasrini 12 ga soddalashtirish mumkin.

$$x\leq 12$$