x(x+2)-(x-1)(x+1) eching

$$x(x+2)-(x-1)(x+1)$$

Baholash

$$2x+1$$

Yechim qadamlari

x ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{2}+2x-\left(x-1\right)\left(x+1\right)$$

Hisoblang: \left(x-1\right)\left(x+1\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}+2x-\left(x^{2}-1^{2}\right)$$

2 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$x^{2}+2x-\left(x^{2}-1\right)$$

x^{2}-1 teskarisini topish uchun har birining teskarisini toping.

$$x^{2}+2x-x^{2}-\left(-1\right)$$

-1 ning teskarisi 1 ga teng.

$$x^{2}+2x-x^{2}+1$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$2x+1$$

Kengaytirish

$$2x+1$$

Yechim qadamlari

x ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{2}+2x-\left(x-1\right)\left(x+1\right)$$

Hisoblang: \left(x-1\right)\left(x+1\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}+2x-\left(x^{2}-1^{2}\right)$$

2 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$x^{2}+2x-\left(x^{2}-1\right)$$

x^{2}-1 teskarisini topish uchun har birining teskarisini toping.

$$x^{2}+2x-x^{2}-\left(-1\right)$$

-1 ning teskarisi 1 ga teng.

$$x^{2}+2x-x^{2}+1$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$2x+1$$