x=4-(3+2z-2y/3) eching

$$x=4-( \frac{ 3+2z-2y }{ 3 } )$$

x uchun yechish

$$x=\frac{2y}{3}-\frac{2z}{3}+3$$

Yechim qadamlari

1+\frac{2}{3}z-\frac{2}{3}y natijani olish uchun 3+2z-2y ning har bir ifodasini 3 ga bo‘ling.

$$x=4-\left(1+\frac{2}{3}z-\frac{2}{3}y\right)$$

1+\frac{2}{3}z-\frac{2}{3}y teskarisini topish uchun har birining teskarisini toping.

$$x=4-1-\frac{2}{3}z+\frac{2}{3}y$$

3 olish uchun 4 dan 1 ni ayirish.

$$x=3-\frac{2}{3}z+\frac{2}{3}y$$

y uchun yechish

$$y=\frac{3x}{2}+z-\frac{9}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

1+\frac{2}{3}z-\frac{2}{3}y natijani olish uchun 3+2z-2y ning har bir ifodasini 3 ga bo‘ling.

$$x=4-\left(1+\frac{2}{3}z-\frac{2}{3}y\right)$$

1+\frac{2}{3}z-\frac{2}{3}y teskarisini topish uchun har birining teskarisini toping.

$$x=4-1-\frac{2}{3}z+\frac{2}{3}y$$

3 olish uchun 4 dan 1 ni ayirish.

$$x=3-\frac{2}{3}z+\frac{2}{3}y$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$3-\frac{2}{3}z+\frac{2}{3}y=x$$

Ikkala tarafdan 3 ni ayirish.

$$-\frac{2}{3}z+\frac{2}{3}y=x-3$$

\frac{2}{3}z ni ikki tarafga qo’shing.

$$\frac{2}{3}y=x-3+\frac{2}{3}z$$

Tenglama standart shaklda.

$$\frac{2}{3}y=\frac{2z}{3}+x-3$$

Tenglamaning ikki tarafini \frac{2}{3} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{\frac{2}{3}y}{\frac{2}{3}}=\frac{\frac{2z}{3}+x-3}{\frac{2}{3}}$$

\frac{2}{3} ga bo'lish \frac{2}{3} ga ko'paytirishni bekor qiladi.

$$y=\frac{\frac{2z}{3}+x-3}{\frac{2}{3}}$$

x-3+\frac{2z}{3} ni \frac{2}{3} ga bo'lish x-3+\frac{2z}{3} ga k'paytirish \frac{2}{3} ga qaytarish.

$$y=\frac{3x}{2}+z-\frac{9}{2}$$