x=-6-2div(y-3) eching

$$x=-6-2 \div (y-3)$$

y uchun yechish

$$y=\frac{3x+16}{x+6}$$

$$x\neq -6$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

y qiymati 3 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini y-3 ga ko'paytirish.

$$x\left(y-3\right)=\left(y-3\right)\left(-6\right)-2$$

x ga y-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$xy-3x=\left(y-3\right)\left(-6\right)-2$$

y-3 ga -6 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$xy-3x=-6y+18-2$$

16 olish uchun 18 dan 2 ni ayirish.

$$xy-3x=-6y+16$$

6y ni ikki tarafga qo’shing.

$$xy-3x+6y=16$$

3x ni ikki tarafga qo’shing.

$$xy+6y=16+3x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x+6\right)y=16+3x$$

Tenglama standart shaklda.

$$\left(x+6\right)y=3x+16$$

Ikki tarafini x+6 ga bo‘ling.

$$\frac{\left(x+6\right)y}{x+6}=\frac{3x+16}{x+6}$$

x+6 ga bo'lish x+6 ga ko'paytirishni bekor qiladi.

$$y=\frac{3x+16}{x+6}$$

y qiymati 3 teng bo‘lmaydi.

$$y=\frac{3x+16}{x+6}\text{, }y\neq 3$$

x uchun yechish

$$x=-\frac{2\left(3y-8\right)}{y-3}$$

$$y\neq 3$$