x=-8y/-12y-6 eching

$$x= \frac{ -8y }{ -12y-6 }$$

y uchun yechish

$$y=\frac{3x}{2\left(2-3x\right)}$$

$$x\neq \frac{2}{3}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

y qiymati -\frac{1}{2} teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 6\left(-2y-1\right) ga ko'paytirish.

$$x\times 6\left(-2y-1\right)=-8y$$

x\times 6 ga -2y-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-12xy-x\times 6=-8y$$

-6 hosil qilish uchun -1 va 6 ni ko'paytirish.

$$-12xy-6x=-8y$$

8y ni ikki tarafga qo’shing.

$$-12xy-6x+8y=0$$

6x ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$-12xy+8y=6x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-12x+8\right)y=6x$$

Tenglama standart shaklda.

$$\left(8-12x\right)y=6x$$

Ikki tarafini -12x+8 ga bo‘ling.

$$\frac{\left(8-12x\right)y}{8-12x}=\frac{6x}{8-12x}$$

-12x+8 ga bo'lish -12x+8 ga ko'paytirishni bekor qiladi.

$$y=\frac{6x}{8-12x}$$

6x ni -12x+8 ga bo'lish.

$$y=\frac{3x}{2\left(2-3x\right)}$$

y qiymati -\frac{1}{2} teng bo‘lmaydi.

$$y=\frac{3x}{2\left(2-3x\right)}\text{, }y\neq -\frac{1}{2}$$

x uchun yechish

$$x=\frac{4y}{3\left(2y+1\right)}$$

$$y\neq -\frac{1}{2}$$