x+x(x-1)=2550 eching

$$x+x(x-1)=2550$$

x uchun yechish

$$x=5\sqrt{102}\approx 50,497524692$$

$$x=-5\sqrt{102}\approx -50,497524692$$

Kvadrat ildizini topish bo'yicha qadamlar

x ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+x^{2}-x=2550$$

0 ni olish uchun x va -x ni birlashtirish.

$$x^{2}=2550$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=5\sqrt{102} x=-5\sqrt{102}$$

Kvadrat tenglamalaridan foydalanish qoidalari

x ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+x^{2}-x=2550$$

0 ni olish uchun x va -x ni birlashtirish.

$$x^{2}=2550$$

Ikkala tarafdan 2550 ni ayirish.

$$x^{2}-2550=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -2550 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2550\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-2550\right)}}{2}$$

-4 ni -2550 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{10200}}{2}$$

10200 ning kvadrat ildizini chiqarish.

$$x=\frac{0±10\sqrt{102}}{2}$$

x=\frac{0±10\sqrt{102}}{2} tenglamasini yeching, bunda ± musbat.

$$x=5\sqrt{102}$$

x=\frac{0±10\sqrt{102}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-5\sqrt{102}$$

Tenglama yechildi.

$$x=5\sqrt{102} x=-5\sqrt{102}$$