x+2>9left(1-xright)^ eching

$$x+2 > 9 { \left(1-x \right) }^{ }$$

x uchun yechish

$$x>\frac{7}{10}$$

Yechim qadamlari

1 daraja ko‘rsatkichini 1-x ga hisoblang va 1-x ni qiymatni oling.

$$x+2>9\left(1-x\right)$$

9 ga 1-x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+2>9-9x$$

9x ni ikki tarafga qo’shing.

$$x+2+9x>9$$

10x ni olish uchun x va 9x ni birlashtirish.

$$10x+2>9$$

Ikkala tarafdan 2 ni ayirish.

$$10x>9-2$$

7 olish uchun 9 dan 2 ni ayirish.

$$10x>7$$

Ikki tarafini 10 ga bo‘ling. 10 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x>\frac{7}{10}$$