xy=frac{-1+sqrt{3}}{2}*frac{-1-sqrt{5i}}{2} eching

$$x y = \frac { - 1 + \sqrt { 3 } } { 2 } \times \frac { - 1 - \sqrt { 5 i } } { 2 }$$

x uchun yechish

$$x=\frac{\left(\sqrt{3}-1\right)\left(\sqrt{10}\left(-1-i\right)-2\right)}{8y}$$

$$y\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 2 ga ko'paytirish.

$$2xy=\left(-1+\sqrt{3}\right)\times \frac{-1-\sqrt{5i}}{2}$$

-1+\sqrt{3} ga \frac{-1-\sqrt{5i}}{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2xy=-\frac{-1-\sqrt{5i}}{2}+\sqrt{3}\times \frac{-1-\sqrt{5i}}{2}$$

-\frac{1}{2}-\frac{1}{2}\sqrt{5i} natijani olish uchun -1-\sqrt{5i} ning har bir ifodasini 2 ga bo‘ling.

$$2xy=-\left(-\frac{1}{2}-\frac{1}{2}\sqrt{5i}\right)+\sqrt{3}\times \frac{-1-\sqrt{5i}}{2}$$

-\frac{1}{2}-\frac{1}{2}\sqrt{5i} teskarisini topish uchun har birining teskarisini toping.

$$2xy=\frac{1}{2}+\frac{1}{2}\sqrt{5i}+\sqrt{3}\times \frac{-1-\sqrt{5i}}{2}$$

-\frac{1}{2}-\frac{1}{2}\sqrt{5i} natijani olish uchun -1-\sqrt{5i} ning har bir ifodasini 2 ga bo‘ling.

$$2xy=\frac{1}{2}+\frac{1}{2}\sqrt{5i}+\sqrt{3}\left(-\frac{1}{2}-\frac{1}{2}\sqrt{5i}\right)$$

\sqrt{3} ga -\frac{1}{2}-\frac{1}{2}\sqrt{5i} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2xy=\frac{1}{2}+\frac{1}{2}\sqrt{5i}-\frac{1}{2}\sqrt{3}-\frac{1}{2}\sqrt{3}\sqrt{5i}$$

Tenglama standart shaklda.

$$2yx=\frac{-\sqrt{3}\sqrt{5i}+\sqrt{5i}+1-\sqrt{3}}{2}$$

Ikki tarafini 2y ga bo‘ling.

$$\frac{2yx}{2y}=\frac{\sqrt{10}\left(\frac{1}{4}+\frac{1}{4}i\right)+\sqrt{30}\left(-\frac{1}{4}-\frac{1}{4}i\right)-\frac{\sqrt{3}}{2}+\frac{1}{2}}{2y}$$

2y ga bo'lish 2y ga ko'paytirishni bekor qiladi.

$$x=\frac{\sqrt{10}\left(\frac{1}{4}+\frac{1}{4}i\right)+\sqrt{30}\left(-\frac{1}{4}-\frac{1}{4}i\right)-\frac{\sqrt{3}}{2}+\frac{1}{2}}{2y}$$

\frac{1}{2}+\left(\frac{1}{4}+\frac{1}{4}i\right)\sqrt{10}-\frac{\sqrt{3}}{2}+\left(-\frac{1}{4}-\frac{1}{4}i\right)\sqrt{30} ni 2y ga bo'lish.

$$x=\frac{\sqrt{10}\left(1+i\right)+\sqrt{30}\left(-1-i\right)+2-2\sqrt{3}}{8y}$$

y uchun yechish

$$y=\frac{\left(\sqrt{3}-1\right)\left(\sqrt{10}\left(-1-i\right)-2\right)}{8x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 2 ga ko'paytirish.

$$2xy=\left(-1+\sqrt{3}\right)\times \frac{-1-\sqrt{5i}}{2}$$

-1+\sqrt{3} ga \frac{-1-\sqrt{5i}}{2} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2xy=-\frac{-1-\sqrt{5i}}{2}+\sqrt{3}\times \frac{-1-\sqrt{5i}}{2}$$

-\frac{1}{2}-\frac{1}{2}\sqrt{5i} natijani olish uchun -1-\sqrt{5i} ning har bir ifodasini 2 ga bo‘ling.

$$2xy=-\left(-\frac{1}{2}-\frac{1}{2}\sqrt{5i}\right)+\sqrt{3}\times \frac{-1-\sqrt{5i}}{2}$$

-\frac{1}{2}-\frac{1}{2}\sqrt{5i} teskarisini topish uchun har birining teskarisini toping.

$$2xy=\frac{1}{2}+\frac{1}{2}\sqrt{5i}+\sqrt{3}\times \frac{-1-\sqrt{5i}}{2}$$

-\frac{1}{2}-\frac{1}{2}\sqrt{5i} natijani olish uchun -1-\sqrt{5i} ning har bir ifodasini 2 ga bo‘ling.

$$2xy=\frac{1}{2}+\frac{1}{2}\sqrt{5i}+\sqrt{3}\left(-\frac{1}{2}-\frac{1}{2}\sqrt{5i}\right)$$

\sqrt{3} ga -\frac{1}{2}-\frac{1}{2}\sqrt{5i} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2xy=\frac{1}{2}+\frac{1}{2}\sqrt{5i}-\frac{1}{2}\sqrt{3}-\frac{1}{2}\sqrt{3}\sqrt{5i}$$

Tenglama standart shaklda.

$$2xy=\frac{-\sqrt{3}\sqrt{5i}+\sqrt{5i}+1-\sqrt{3}}{2}$$

Ikki tarafini 2x ga bo‘ling.

$$\frac{2xy}{2x}=\frac{\sqrt{10}\left(\frac{1}{4}+\frac{1}{4}i\right)+\sqrt{30}\left(-\frac{1}{4}-\frac{1}{4}i\right)-\frac{\sqrt{3}}{2}+\frac{1}{2}}{2x}$$

2x ga bo'lish 2x ga ko'paytirishni bekor qiladi.

$$y=\frac{\sqrt{10}\left(\frac{1}{4}+\frac{1}{4}i\right)+\sqrt{30}\left(-\frac{1}{4}-\frac{1}{4}i\right)-\frac{\sqrt{3}}{2}+\frac{1}{2}}{2x}$$

\frac{1}{2}+\left(\frac{1}{4}+\frac{1}{4}i\right)\sqrt{10}-\frac{\sqrt{3}}{2}+\left(-\frac{1}{4}-\frac{1}{4}i\right)\sqrt{30} ni 2x ga bo'lish.

$$y=\frac{\sqrt{10}\left(1+i\right)+\sqrt{30}\left(-1-i\right)+2-2\sqrt{3}}{8x}$$