x_1^2-2-(x-0.8)=-2(0.9+x) eching

$$x _ { 1 } ^ { 2 } - 2 - ( x - 0.8 ) = - 2 ( 0.9 + x )$$

x uchun yechish

$$x=-\left(x_{1}^{2}+0,6\right)$$

Yechim qadamlari

x-0,8 teskarisini topish uchun har birining teskarisini toping.

$$x_{1}^{2}-2-x+0,8=-2\left(0,9+x\right)$$

-1,2 olish uchun -2 va 0,8'ni qo'shing.

$$x_{1}^{2}-1,2-x=-2\left(0,9+x\right)$$

-2 ga 0,9+x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x_{1}^{2}-1,2-x=-1,8-2x$$

2x ni ikki tarafga qo’shing.

$$x_{1}^{2}-1,2-x+2x=-1,8$$

x ni olish uchun -x va 2x ni birlashtirish.

$$x_{1}^{2}-1,2+x=-1,8$$

Ikkala tarafdan x_{1}^{2} ni ayirish.

$$-1,2+x=-1,8-x_{1}^{2}$$

1,2 ni ikki tarafga qo’shing.

$$x=-1,8-x_{1}^{2}+1,2$$

-0,6 olish uchun -1,8 va 1,2'ni qo'shing.

$$x=-0,6-x_{1}^{2}$$

x_1 uchun yechish (complex solution)

$$x_{1}=-i\sqrt{x+0,6}$$

$$x_{1}=i\sqrt{x+0,6}$$

x_1 uchun yechish

$$x_{1}=\frac{\sqrt{-4x-2,4}}{2}$$

$$x_{1}=-\frac{\sqrt{-4x-2,4}}{2}\text{, }x\leq -\frac{3}{5}$$