x-3=1/6(x-3+b+8) eching

$$x - 3 = \frac { 1 } { 6 } ( x - 3 + b + 8 )$$

b uchun yechish

$$b=5x-23$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5 olish uchun -3 va 8'ni qo'shing.

$$x-3=\frac{1}{6}\left(x+5+b\right)$$

\frac{1}{6} ga x+5+b ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x-3=\frac{1}{6}x+\frac{5}{6}+\frac{1}{6}b$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{1}{6}x+\frac{5}{6}+\frac{1}{6}b=x-3$$

Ikkala tarafdan \frac{1}{6}x ni ayirish.

$$\frac{5}{6}+\frac{1}{6}b=x-3-\frac{1}{6}x$$

\frac{5}{6}x ni olish uchun x va -\frac{1}{6}x ni birlashtirish.

$$\frac{5}{6}+\frac{1}{6}b=\frac{5}{6}x-3$$

Ikkala tarafdan \frac{5}{6} ni ayirish.

$$\frac{1}{6}b=\frac{5}{6}x-3-\frac{5}{6}$$

-\frac{23}{6} olish uchun -3 dan \frac{5}{6} ni ayirish.

$$\frac{1}{6}b=\frac{5}{6}x-\frac{23}{6}$$

Tenglama standart shaklda.

$$\frac{1}{6}b=\frac{5x-23}{6}$$

Ikkala tarafini 6 ga ko‘paytiring.

$$\frac{\frac{1}{6}b}{\frac{1}{6}}=\frac{5x-23}{\frac{1}{6}\times 6}$$

\frac{1}{6} ga bo'lish \frac{1}{6} ga ko'paytirishni bekor qiladi.

$$b=\frac{5x-23}{\frac{1}{6}\times 6}$$

\frac{5x-23}{6} ni \frac{1}{6} ga bo'lish \frac{5x-23}{6} ga k'paytirish \frac{1}{6} ga qaytarish.

$$b=5x-23$$

x uchun yechish

$$x=\frac{b+23}{5}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5 olish uchun -3 va 8'ni qo'shing.

$$x-3=\frac{1}{6}\left(x+5+b\right)$$

\frac{1}{6} ga x+5+b ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x-3=\frac{1}{6}x+\frac{5}{6}+\frac{1}{6}b$$

Ikkala tarafdan \frac{1}{6}x ni ayirish.

$$x-3-\frac{1}{6}x=\frac{5}{6}+\frac{1}{6}b$$

\frac{5}{6}x ni olish uchun x va -\frac{1}{6}x ni birlashtirish.

$$\frac{5}{6}x-3=\frac{5}{6}+\frac{1}{6}b$$

3 ni ikki tarafga qo’shing.

$$\frac{5}{6}x=\frac{5}{6}+\frac{1}{6}b+3$$

\frac{23}{6} olish uchun \frac{5}{6} va 3'ni qo'shing.

$$\frac{5}{6}x=\frac{23}{6}+\frac{1}{6}b$$

Tenglama standart shaklda.

$$\frac{5}{6}x=\frac{b+23}{6}$$

Tenglamaning ikki tarafini \frac{5}{6} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{\frac{5}{6}x}{\frac{5}{6}}=\frac{b+23}{\frac{5}{6}\times 6}$$

\frac{5}{6} ga bo'lish \frac{5}{6} ga ko'paytirishni bekor qiladi.

$$x=\frac{b+23}{\frac{5}{6}\times 6}$$

\frac{23+b}{6} ni \frac{5}{6} ga bo'lish \frac{23+b}{6} ga k'paytirish \frac{5}{6} ga qaytarish.

$$x=\frac{b+23}{5}$$