x(x+2)(x+2)+2(x+2)(x-2) eching

$$x ( x + 2 ) ( x + 2 ) + 2 ( x + 2 ) ( x - 2 )$$

Baholash

$$\left(x+2\right)\left(x\left(x+4\right)-4\right)$$

Yechim qadamlari

\left(x+2\right)^{2} hosil qilish uchun x+2 va x+2 ni ko'paytirish.

$$x\left(x+2\right)^{2}+2\left(x+2\right)\left(x-2\right)$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+2\right)^{2} kengaytirilishi uchun ishlating.

$$x\left(x^{2}+4x+4\right)+2\left(x+2\right)\left(x-2\right)$$

x ga x^{2}+4x+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+4x^{2}+4x+2\left(x+2\right)\left(x-2\right)$$

2 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+4x^{2}+4x+\left(2x+4\right)\left(x-2\right)$$

2x+4 ifodaning har bir elementini x-2 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$x^{3}+4x^{2}+4x+2x^{2}-4x+4x-8$$

0 ni olish uchun -4x va 4x ni birlashtirish.

$$x^{3}+4x^{2}+4x+2x^{2}-8$$

6x^{2} ni olish uchun 4x^{2} va 2x^{2} ni birlashtirish.

$$x^{3}+6x^{2}+4x-8$$

Kengaytirish

$$x^{3}+6x^{2}+4x-8$$

Yechim qadamlari

\left(x+2\right)^{2} hosil qilish uchun x+2 va x+2 ni ko'paytirish.

$$x\left(x+2\right)^{2}+2\left(x+2\right)\left(x-2\right)$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+2\right)^{2} kengaytirilishi uchun ishlating.

$$x\left(x^{2}+4x+4\right)+2\left(x+2\right)\left(x-2\right)$$

x ga x^{2}+4x+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+4x^{2}+4x+2\left(x+2\right)\left(x-2\right)$$

2 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+4x^{2}+4x+\left(2x+4\right)\left(x-2\right)$$

2x+4 ifodaning har bir elementini x-2 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$x^{3}+4x^{2}+4x+2x^{2}-4x+4x-8$$

0 ni olish uchun -4x va 4x ni birlashtirish.

$$x^{3}+4x^{2}+4x+2x^{2}-8$$

6x^{2} ni olish uchun 4x^{2} va 2x^{2} ni birlashtirish.

$$x^{3}+6x^{2}+4x-8$$