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x \sqrt{40} + 3 \cdot 0,9975640502598242 = 70
Evaluate trigonometric functions in the problem
x\times 2\sqrt{10}+3\times 0,9975640502598242=70
Faktor: 40=2^{2}\times 10. \sqrt{2^{2}\times 10} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{10} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.
x\times 2\sqrt{10}+2,9926921507794726=70
2,9926921507794726 hosil qilish uchun 3 va 0,9975640502598242 ni ko'paytirish.
x\times 2\sqrt{10}=70-2,9926921507794726
Ikkala tarafdan 2,9926921507794726 ni ayirish.
x\times 2\sqrt{10}=67,0073078492205274
67,0073078492205274 olish uchun 70 dan 2,9926921507794726 ni ayirish.
2\sqrt{10}x=67,0073078492205274
Tenglama standart shaklda.
\frac{2\sqrt{10}x}{2\sqrt{10}}=\frac{67,0073078492205274}{2\sqrt{10}}
Ikki tarafini 2\sqrt{10} ga bo‘ling.
x=\frac{67,0073078492205274}{2\sqrt{10}}
2\sqrt{10} ga bo'lish 2\sqrt{10} ga ko'paytirishni bekor qiladi.
x=\frac{335036539246102637\sqrt{10}}{100000000000000000}
67,0073078492205274 ni 2\sqrt{10} ga bo'lish.