x^y-dx-k=0 eching

$$x ^ { y } - d x - k = 0$$

d uchun yechish (complex solution)

$$\left\{\begin{matrix}d=\frac{x^{y}-k}{x}\text{, }&x\neq 0\\d\in \mathrm{C}\text{, }&x=0\text{ and }k=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{y} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-dx-k=-x^{y}$$

k ni ikki tarafga qo’shing.

$$-dx=-x^{y}+k$$

Tenglama standart shaklda.

$$\left(-x\right)d=k-x^{y}$$

Ikki tarafini -x ga bo‘ling.

$$\frac{\left(-x\right)d}{-x}=\frac{k-x^{y}}{-x}$$

-x ga bo'lish -x ga ko'paytirishni bekor qiladi.

$$d=\frac{k-x^{y}}{-x}$$

k-x^{y} ni -x ga bo'lish.

$$d=-\frac{k-x^{y}}{x}$$

k uchun yechish (complex solution)

$$k=x^{y}-dx$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{y} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-dx-k=-x^{y}$$

dx ni ikki tarafga qo’shing.

$$-k=-x^{y}+dx$$

Tenglama standart shaklda.

$$-k=dx-x^{y}$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-k}{-1}=\frac{dx-x^{y}}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$k=\frac{dx-x^{y}}{-1}$$

-x^{y}+dx ni -1 ga bo'lish.

$$k=x^{y}-dx$$

d uchun yechish

$$\left\{\begin{matrix}d=\frac{x^{y}-k}{x}\text{, }&x>0\text{ or }\left(Denominator(y)\text{bmod}2=1\text{ and }x<0\right)\\d\in \mathrm{R}\text{, }&x=0\text{ and }k=0\text{ and }y>0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{y} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-dx-k=-x^{y}$$

k ni ikki tarafga qo’shing.

$$-dx=-x^{y}+k$$

Tenglama standart shaklda.

$$\left(-x\right)d=k-x^{y}$$

Ikki tarafini -x ga bo‘ling.

$$\frac{\left(-x\right)d}{-x}=\frac{k-x^{y}}{-x}$$

-x ga bo'lish -x ga ko'paytirishni bekor qiladi.

$$d=\frac{k-x^{y}}{-x}$$

k-x^{y} ni -x ga bo'lish.

$$d=-\frac{k-x^{y}}{x}$$

k uchun yechish

$$k=x^{y}-dx$$

$$\left(x<0\text{ and }Denominator(y)\text{bmod}2=1\right)\text{ or }\left(x=0\text{ and }y>0\right)\text{ or }x>0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{y} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-dx-k=-x^{y}$$

dx ni ikki tarafga qo’shing.

$$-k=-x^{y}+dx$$

Tenglama standart shaklda.

$$-k=dx-x^{y}$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-k}{-1}=\frac{dx-x^{y}}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$k=\frac{dx-x^{y}}{-1}$$

-x^{y}+dx ni -1 ga bo'lish.

$$k=x^{y}-dx$$