x^6+1 eching

$$x ^ { 6 } + 1$$

Omil

$$\left(x^{2}+1\right)\left(x^{4}-x^{2}+1\right)$$

Yechim qadamlari

x^{6}+1 ni \left(x^{2}\right)^{3}+1^{3} sifatida qaytadan yozish. Kublar yigʻindisini ushbu formula bilan hisoblash mumkin: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). Quyidagi koʻphadlar faktorlanmagan, ularda hech qanday ratsional ildizlar topilmadi: x^{4}-x^{2}+1,x^{2}+1.

$$\left(x^{2}+1\right)\left(x^{4}-x^{2}+1\right)$$

Baholash

$$x^{6}+1$$