x^3+6x^2-16x-96 eching

$$x ^ { 3 } + 6 x ^ { 2 } - 16 x - 96$$

Omil

$$\left(x-4\right)\left(x+4\right)\left(x+6\right)$$

Yechim qadamlari

x^{3}+6x^{2}-16x-96=\left(x^{3}+6x^{2}\right)+\left(-16x-96\right) misolini guruhlang hamda x^{2} ni birinchi va -16 ni ikkinchi guruhdan ajrating.

$$x^{2}\left(x+6\right)-16\left(x+6\right)$$

Distributiv funktsiyasidan foydalangan holda x+6 umumiy terminini chiqaring.

$$\left(x+6\right)\left(x^{2}-16\right)$$

Hisoblang: x^{2}-16. x^{2}-16 ni x^{2}-4^{2} sifatida qaytadan yozish. Kvadratlarning farqini ushbu formula bilan hisoblash mumkin: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-4\right)\left(x+4\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$\left(x-4\right)\left(x+4\right)\left(x+6\right)$$

Baholash

$$\left(x+6\right)\left(x^{2}-16\right)$$