x^2-ax+9=0 eching

$$x ^ { 2 } - a x + 9 = 0$$

a uchun yechish

$$a=x+\frac{9}{x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-ax+9=-x^{2}$$

Ikkala tarafdan 9 ni ayirish.

$$-ax=-x^{2}-9$$

Tenglama standart shaklda.

$$\left(-x\right)a=-x^{2}-9$$

Ikki tarafini -x ga bo‘ling.

$$\frac{\left(-x\right)a}{-x}=\frac{-x^{2}-9}{-x}$$

-x ga bo'lish -x ga ko'paytirishni bekor qiladi.

$$a=\frac{-x^{2}-9}{-x}$$

-x^{2}-9 ni -x ga bo'lish.

$$a=x+\frac{9}{x}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{a^{2}-36}+a}{2}$$

$$x=\frac{-\sqrt{a^{2}-36}+a}{2}$$

x uchun yechish

$$x=\frac{\sqrt{a^{2}-36}+a}{2}$$

$$x=\frac{-\sqrt{a^{2}-36}+a}{2}\text{, }|a|\geq 6$$