x^2-ab-a^2=bx eching

$$x ^ { 2 } - a b - a ^ { 2 } = b x$$

b uchun yechish (complex solution)

$$\left\{\begin{matrix}\\b=x-a\text{, }&\text{unconditionally}\\b\in \mathrm{C}\text{, }&x=-a\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan bx ni ayirish.

$$x^{2}-ab-a^{2}-bx=0$$

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-ab-a^{2}-bx=-x^{2}$$

a^{2} ni ikki tarafga qo’shing.

$$-ab-bx=-x^{2}+a^{2}$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-a-x\right)b=-x^{2}+a^{2}$$

Tenglama standart shaklda.

$$\left(-x-a\right)b=a^{2}-x^{2}$$

Ikki tarafini -a-x ga bo‘ling.

$$\frac{\left(-x-a\right)b}{-x-a}=\frac{\left(a-x\right)\left(x+a\right)}{-x-a}$$

-a-x ga bo'lish -a-x ga ko'paytirishni bekor qiladi.

$$b=\frac{\left(a-x\right)\left(x+a\right)}{-x-a}$$

\left(x+a\right)\left(-x+a\right) ni -a-x ga bo'lish.

$$b=x-a$$

b uchun yechish

$$\left\{\begin{matrix}\\b=x-a\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&x=-a\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan bx ni ayirish.

$$x^{2}-ab-a^{2}-bx=0$$

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-ab-a^{2}-bx=-x^{2}$$

a^{2} ni ikki tarafga qo’shing.

$$-ab-bx=-x^{2}+a^{2}$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-a-x\right)b=-x^{2}+a^{2}$$

Tenglama standart shaklda.

$$\left(-x-a\right)b=a^{2}-x^{2}$$

Ikki tarafini -a-x ga bo‘ling.

$$\frac{\left(-x-a\right)b}{-x-a}=\frac{\left(a-x\right)\left(x+a\right)}{-x-a}$$

-a-x ga bo'lish -a-x ga ko'paytirishni bekor qiladi.

$$b=\frac{\left(a-x\right)\left(x+a\right)}{-x-a}$$

\left(x+a\right)\left(-x+a\right) ni -a-x ga bo'lish.

$$b=x-a$$

a uchun yechish

$$a=-x$$

$$a=x-b$$