x^2-63=0 eching

$$x ^ { 2 } - 63 = 0$$

x uchun yechish

$$x=3\sqrt{7}\approx 7,937253933$$

$$x=-3\sqrt{7}\approx -7,937253933$$

Kvadrat ildizini topish bo'yicha qadamlar

63 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$x^{2}=63$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=3\sqrt{7} x=-3\sqrt{7}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$x^{2}-63=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -63 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-63\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-63\right)}}{2}$$

-4 ni -63 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{252}}{2}$$

252 ning kvadrat ildizini chiqarish.

$$x=\frac{0±6\sqrt{7}}{2}$$

x=\frac{0±6\sqrt{7}}{2} tenglamasini yeching, bunda ± musbat.

$$x=3\sqrt{7}$$

x=\frac{0±6\sqrt{7}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-3\sqrt{7}$$

Tenglama yechildi.

$$x=3\sqrt{7} x=-3\sqrt{7}$$