x^2-4xy+x-5=0 eching

$$x ^ { 2 } - 4 x y + x - 5 = 0$$

y uchun yechish

$$y=\frac{x}{4}+\frac{1}{4}-\frac{5}{4x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-4xy+x-5=-x^{2}$$

Ikkala tarafdan x ni ayirish.

$$-4xy-5=-x^{2}-x$$

5 ni ikki tarafga qo’shing.

$$-4xy=-x^{2}-x+5$$

Tenglama standart shaklda.

$$\left(-4x\right)y=5-x-x^{2}$$

Ikki tarafini -4x ga bo‘ling.

$$\frac{\left(-4x\right)y}{-4x}=\frac{5-x-x^{2}}{-4x}$$

-4x ga bo'lish -4x ga ko'paytirishni bekor qiladi.

$$y=\frac{5-x-x^{2}}{-4x}$$

-x^{2}-x+5 ni -4x ga bo'lish.

$$y=\frac{x}{4}+\frac{1}{4}-\frac{5}{4x}$$

x uchun yechish

$$x=\frac{\sqrt{16y^{2}-8y+21}}{2}+2y-\frac{1}{2}$$

$$x=-\frac{\sqrt{16y^{2}-8y+21}}{2}+2y-\frac{1}{2}$$