x^2-4x-8y+12=0 eching

$$x ^ { 2 } - 4 x - 8 y + 12 = 0$$

y uchun yechish

$$y=\frac{x^{2}-4x+12}{8}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-4x-8y+12=-x^{2}$$

4x ni ikki tarafga qo’shing.

$$-8y+12=-x^{2}+4x$$

Ikkala tarafdan 12 ni ayirish.

$$-8y=-x^{2}+4x-12$$

Ikki tarafini -8 ga bo‘ling.

$$\frac{-8y}{-8}=\frac{-x^{2}+4x-12}{-8}$$

-8 ga bo'lish -8 ga ko'paytirishni bekor qiladi.

$$y=\frac{-x^{2}+4x-12}{-8}$$

-x^{2}+4x-12 ni -8 ga bo'lish.

$$y=\frac{x^{2}}{8}-\frac{x}{2}+\frac{3}{2}$$

x uchun yechish (complex solution)

$$x=2\sqrt{2y-2}+2$$

$$x=-2\sqrt{2y-2}+2$$

x uchun yechish

$$x=2\sqrt{2y-2}+2$$

$$x=-2\sqrt{2y-2}+2\text{, }y\geq 1$$