x^2-4x-5*8 eching

$$x ^ { 2 } - 4 x - 5 \cdot 8$$

Omil

$$\left(x-\left(2-2\sqrt{11}\right)\right)\left(x-\left(2\sqrt{11}+2\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

40 hosil qilish uchun 5 va 8 ni ko'paytirish.

$$factor(x^{2}-4x-40)$$

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}-4x-40=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\left(-40\right)}}{2}$$

-4 kvadratini chiqarish.

$$x=\frac{-\left(-4\right)±\sqrt{16-4\left(-40\right)}}{2}$$

-4 ni -40 marotabaga ko'paytirish.

$$x=\frac{-\left(-4\right)±\sqrt{16+160}}{2}$$

16 ni 160 ga qo'shish.

$$x=\frac{-\left(-4\right)±\sqrt{176}}{2}$$

176 ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-4\right)±4\sqrt{11}}{2}$$

-4 ning teskarisi 4 ga teng.

$$x=\frac{4±4\sqrt{11}}{2}$$

x=\frac{4±4\sqrt{11}}{2} tenglamasini yeching, bunda ± musbat. 4 ni 4\sqrt{11} ga qo'shish.

$$x=\frac{4\sqrt{11}+4}{2}$$

4+4\sqrt{11} ni 2 ga bo'lish.

$$x=2\sqrt{11}+2$$

x=\frac{4±4\sqrt{11}}{2} tenglamasini yeching, bunda ± manfiy. 4 dan 4\sqrt{11} ni ayirish.

$$x=\frac{4-4\sqrt{11}}{2}$$

4-4\sqrt{11} ni 2 ga bo'lish.

$$x=2-2\sqrt{11}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 2+2\sqrt{11} ga va x_{2} uchun 2-2\sqrt{11} ga bo‘ling.

$$x^{2}-4x-40=\left(x-\left(2\sqrt{11}+2\right)\right)\left(x-\left(2-2\sqrt{11}\right)\right)$$

Baholash

$$x^{2}-4x-40$$

Yechim qadamlari

40 hosil qilish uchun 5 va 8 ni ko'paytirish.

$$x^{2}-4x-40$$